解决超话签到中选择性签到的逻辑问题

backend/task_scheduler/app/main.py

@@ -369,6 +369,7 @@ async def _async_do_signin(account_id: str, cron_expr: str = ""):
                 return {"status": "failed", "reason": "cookie decryption failed"}
 
             acc_id = str(account.id)
+            acc_selected_topics = account.selected_topics  # 用户选择的超话列表
     except Exception as e:
         await eng.dispose()
         raise e
@@ -387,6 +388,16 @@ async def _async_do_signin(account_id: str, cron_expr: str = ""):
                     await session.commit()
             return {"status": "completed", "signed": 0, "message": "no topics"}
 
+        # 如果用户选择了特定超话，只签选中的
+        if acc_selected_topics and isinstance(acc_selected_topics, list):
+            selected_cids = {t.get("containerid") for t in acc_selected_topics if t.get("containerid")}
+            if selected_cids:
+                topics = [t for t in topics if t["containerid"] in selected_cids]
+                logger.info(f"📌 按用户选择过滤: {len(topics)} 个超话 (共 {len(selected_cids)} 个已选)")
+
+        if not topics:
+            return {"status": "completed", "signed": 0, "message": "no selected topics"}
+
         signed = already = failed = 0
         log_entries = []